Hooke's Law states that:

"The extension of a spring is directly proportional to the load applied, provided the limit of proportionality is not exceeded."

The stiffness (k) of a spring, measured in Nm-1 (Newtons per Meter) is the force required to stretch it by 1 meter.

So: F=ke (Force = Stiffness x Extension)

Hooke's law, written in a simple equation, is simply this:

F=kx

where F is the force required to push the spring, k is the spring constant (stiffness), different for every spring and x is the distance the spring is pushed or pulles. If we are pushing, though, the spring will be pushing back on us with an equal and opposite force. This can obviously be expressed as:

F=-kx

where F is the force of the spring pushing back on whatever force is pushing it. This law is accurate for all linear springs so long as x is not too great.

In order to use this in most cases, we must put this force in terms of work, which should be:

W=kx

Yet 'F' is not a single value, but increases linearly with x.
We must use the average force, which is 0.5(0+kx), or 0.5kx. In other words, we have W=Favgx=(0.5kx)(x)=0.5kx2. Since the change in potential energy is equivalent to the work done, we can write the elastic potential is this:

Up=0.5kx2.

This equation works equally well if you're pulling the spring.

In 1676, Robert Hooke announced his eponymous natural law to the physics community in the form of the anagram ceiiinosssttuv. Rearranged it spells "ut tensio sic vis;" Latin for the now-well-known Hooke's Law: the stretch (of a spring) is proportional to the force (F=-kx).

Log in or register to write something here or to contact authors.